java bit manipulation

Question

byte x = -1;
for(int i = 0; i < 8; i++)
{
    x = (byte) (x >>> 1);
    System.out.println(\"X: \" + x);
}

As I understand it, java sto

Answer 1

The problem is, as told before (long time ago), that x get upcasted to int (sign-extended) before doing the shift.
Doing a "bit-to-bit" conversion should help:

byte x = -1;
for(int i = 0; i < 8; i++)
{
    x = (byte) ((x & 0xFF) >>> 1);
    System.out.println("X: " + x);
}