Understanding typedefs for function pointers in C

Question

I have always been a bit stumped when I read other peoples\' code which had typedefs for pointers to functions with arguments. I recall that it took me a while to get around

Answer 1

This is the simplest example of function pointers and function pointer arrays that I wrote as an exercise.

    typedef double (*pf)(double x);  /*this defines a type pf */

    double f1(double x) { return(x+x);}
    double f2(double x) { return(x*x);}

    pf pa[] = {f1, f2};


    main()
    {
        pf p;

        p = pa[0];
        printf("%f\n", p(3.0));
        p = pa[1];
        printf("%f\n", p(3.0));
    }