regular expression in iOS

Question

I am looking for a regular expression to match the following -100..100:0.01. The meaning of this expression is that the value can increment by 0.01 and should b

Answer 1

You could use NSRegularExpression instead. It does support \b, btw, though you have to escape it in the string:

NSString *regex = @"\\b-?1?[0-9]{2}(\\.[0-9]{1,2})?\\b";

Though, I think \\W would be a better idea, since \\b messes up detecting the negative sign on the number.

A hopefully better example:

NSString *string = <...your source string...>;
NSError  *error  = NULL;

NSRegularExpression *regex = [NSRegularExpression 
  regularExpressionWithPattern:@"\\W-?1?[0-9]{2}(\\.[0-9]{1,2})?\\W"
                       options:0
                         error:&error];

NSRange range   = [regex rangeOfFirstMatchInString:string
                              options:0 
                              range:NSMakeRange(0, [string length])];
NSString *result = [string substringWithRange:range];

I hope this helps. :)

EDIT: fixed based on the below comment.