How do I pass an equal sign when calling a batch script in Powershell?

Question

We have a batch file that invokes our MSBuild-based build process. Syntax:

build App Target [ Additional MSBuild Arguments ]

Internally, i

Answer 1

I don't know if there's an easier answer (I think not) but you can solve the problem by using .Net's process class to invoke cmd.exe. Here's an example:

# use .NET Process class to run a batch file, passing it an argument that contains an equals sign. 
# This test script assumes the existence of a batch file "c:\temp\test.bat"
# that has this content:
#      echo %1
#      pause
$cmdLine =  $cmdLine =  '/c c:\temp\test.bat "x=1"'
$procStartInfo =  new-object System.Diagnostics.ProcessStartInfo("cmd", $cmdLine )
$proc = new-object System.Diagnostics.Process
$proc.StartInfo = $procStartInfo
$proc.Start();