PHP: 'or' statement on instruction fail: how to throw a new exception?

Question

Everyone here should know the \'or\' statemens, usually glued to an die() command:

$foo = bar() or die(\'Error: bar function return false.\');

Answer 1

You can also create a custom exception class and use it's static constructor method instead of throw new Exception() construction.

Exception class:

class CustomException extends Exception {
  static public function doThrow($message = "", $code = 0, Exception $previous = null) {
    throw new Exception($message, $code, $previous);
  }
}

Usage:

try {

  $foo = bar() or CustomException::doThrow('Problems with bar()');
  $aa = bb($foo) or CustomException::doThrow('Problems with bb()');

} catch(Exception $e){
  echo $e->getMessage();
}

Note

If you are using PHP 7 and higher - you can rename static method doThrow() to simply throw(), since in PHP 7 and higher it's allowed to use reserved keywords as method names.