Generate/get xpath from XML node java

Question

I\'m interested in advice/pseudocode code/explanation rather than actual implementation.

• I\'d like to go trough xml document

Answer 1

Update:

@c0mrade has updated his question. Here is a solution to it:

This XSLT transformation:

    
    

    '

    
      
         
         
         

        
        
    

    
        
        
        
            
        
    

    
        
        
        

    

when applied on the provided XML document:

    one
    two
    three
    four
    
        five
    

produces exactly the wanted, correct result:

/root/elemA='one'
/root/elemA[2]='two'
/root/elemA[2][@attribute1='first']
/root/elemA[2][@attribute2='second']
/root/elemB='three'
/root/elemA[3]='four'
/root/elemC/elemB='five'

When applied to the newly-provided document by @c0mrade:

    
        89734
    

again the correct result is produced:

/root/elemX='89734'
/root/elemX[@serial='kefw90234kf2esda9231']

Explanation:

• Only elements that have no children elements, or have attributes are matched and processed.

• For any such element, if it doesn't have children-elements all of its ancestor-or self elements are processed in a specific mode, named 'path'. Then the "='theValue'" part is output and then a NL character.

• All attributes of the matched element are then processed.

• Then finally, templates are applied to all children-elements.

• Processing an element in the 'path' mode is simple: A / character and the name of the element are output. Then, if there are preceding siblings with the same name, a "[numPrecSiblings+1]` part is output.

• Processing of attributes is simple: First all ancestor-or-self:: elements of its parent are processed in 'path' mode, then the [attrName=attrValue] part is output, followed by a NL character.

Do note:

• Names that are in a namespace are displayed without any problem and in their initial readable form.

• To aid readability, an index of [1] is never displayed.

---

Below is my initial answer (may be ignored)

Here is a pure XSLT 1.0 solution:

Below is a sample xml document and a stylesheet that takes a node-set parameter and produces one valid XPath expression for every member-node.

stylesheet (buildPath.xsl):

---

  
    
    
    
      /
      
                   
          
            
            
            
            
              
            
          
        
         
          
               
            
              
                
              
                 
              
              
                
                
                
                
                  
                
              
                 
            
            
              
                
                
                
                
                  
                
              
                 
               
              
                
                
                
                
                  
                
              
                 
            
            

              '
              
                

              
                 
          
                    
      
    
    

  
 
 

xml source (buildPath.xml):

---

    textA
 
  
        xxxxxxxx
  
        
  
   
  
        
        yyyyyyy
  
  
    

Result:

/root/nodeA[2]/nodeB[2]/namespace::*[local-name() = 'myNamespace']
/root/nodeA[2]/nodeB[2]/nodeC/namespace::*[local-name() =
'myNamespace']