C++ destruction of temporary object in an expression

Question

Given the following code:

#include 

struct implicit_t
{
    implicit_t(int x) :
        x_m(x)
    {
        std::cout << \"ctor\" <         


        

Answer 1

Temporary objects are destroyed as the last step in evaluating the full-expression (1.9) that (lexically) contains the point where they were created. [12.2/3]