Find the first non-repeated character in a string

Question

I read of a job interview question to write some code for the following:

Write an efficient function to find the first nonrepeated character in a st

Answer 1

# I came up with another solution but not efficient comment?
str1 = "awbkkzafrocfbvwcqbb"
list1 = []
count = 0
newlen = len(str1)
find = False


def myfun(count, str1, list1, newlen):

    for i in range(count, newlen):

        if i == 0:

            list1.append(str1[i])

        else:
            if str1[i] in list1:
                str1 = str1.translate({ord(str1[i]): None})
                print(str1)
                newlen = len(str1)
                count =0
                i = count
                list1.pop()
                myfun(count,str1,list1,newlen)
            else:
                pass

    if str1.find(list1[0], 1, len(str1)) != -1 :
        pass
    else:
        print(list1[0]+" is your first non repeating character")
        exit()


myfun(count, str1, list1, newlen)