I always thought that && operator in Java is used for verifying whether both its boolean operands are true, and the & oper
Besides && and || being short circuiting, also consider operator precedence when mixing the two forms. I think it will not be immediately apparent to everybody that result1 and result2 contain different values.
boolean a = true;
boolean b = false;
boolean c = false;
boolean result1 = a || b && c; //is true; evaluated as a || (b && c)
boolean result2 = a | b && c; //is false; evaluated as (a | b) && c