Compare two arrays of objects and remove items in the second one that have the same property value

Question

All I need to do is compare two arrays of objects and remove items in the second one that have the same property value. For example:

var a = [{\'name\':\'bob         


        

Answer 1

let A = [
  {name: 'a', age: 20},
  {name: 'b', age: 30},
  {name: 'c', age: 10},
]

let B = [
  {name: 'a', age: 20},
  {name: 'b', age: 40},
  {name: 'd', age: 10},
  {name: 'e', age: 20},
  {name: 'f', age: 10},
]

const compareName = (obj1, obj2)=>{
  return (obj1.name === obj2.name);
}

const compareAll = (obj1, obj2)=>{
  return (obj1.name === obj2.name && obj1.age=== obj2.age);
}

let output = B.filter(b=>{
  let indexFound = A.findIndex(a => compareName(a, b));
  return indexFound == -1;
})

Depending on which Objects you want to remove use:

1. compareName : Remove objects which have common name
2. compareAll : Remove objects which have both name & age common

Also to find common Objects list just add use return index != -1

PS: Refer my Github for Array Data Manipulation examples in Javascript