How to map a composite key with JPA and Hibernate?

Question

In this code, how to generate a Java class for the composite key (how to composite key in hibernate):

create table Time (
     levelStation int(15) not null,         


        

Answer 1

As I explained in this article, assuming you have the following database tables:

First, you need to create the @Embeddable holding the composite identifier:

@Embeddable
public class EmployeeId implements Serializable {

    @Column(name = "company_id")
    private Long companyId;

    @Column(name = "employee_number")
    private Long employeeNumber;

    public EmployeeId() {
    }

    public EmployeeId(Long companyId, Long employeeId) {
        this.companyId = companyId;
        this.employeeNumber = employeeId;
    }

    public Long getCompanyId() {
        return companyId;
    }

    public Long getEmployeeNumber() {
        return employeeNumber;
    }

    @Override
    public boolean equals(Object o) {
        if (this == o) return true;
        if (!(o instanceof EmployeeId)) return false;
        EmployeeId that = (EmployeeId) o;
        return Objects.equals(getCompanyId(), that.getCompanyId()) &&
                Objects.equals(getEmployeeNumber(), that.getEmployeeNumber());
    }

    @Override
    public int hashCode() {
        return Objects.hash(getCompanyId(), getEmployeeNumber());
    }
}

With this in place, we can map the Employee entity which uses the composite identifier by annotating it with @EmbeddedId:

@Entity(name = "Employee")
@Table(name = "employee")
public class Employee {

    @EmbeddedId
    private EmployeeId id;

    private String name;

    public EmployeeId getId() {
        return id;
    }

    public void setId(EmployeeId id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }
}

The Phone entity which has a @ManyToOne association to Employee, needs to reference the composite identifier from the parent class via two @JoinColumnmappings:

@Entity(name = "Phone")
@Table(name = "phone")
public class Phone {

    @Id
    @Column(name = "`number`")
    private String number;

    @ManyToOne
    @JoinColumns({
        @JoinColumn(
            name = "company_id",
            referencedColumnName = "company_id"),
        @JoinColumn(
            name = "employee_number",
            referencedColumnName = "employee_number")
    })
    private Employee employee;

    public Employee getEmployee() {
        return employee;
    }

    public void setEmployee(Employee employee) {
        this.employee = employee;
    }

    public String getNumber() {
        return number;
    }

    public void setNumber(String number) {
        this.number = number;
    }
}

For more details, check out this article.