I\'m trying to execute the following
>> from numpy import *
>> x = array([[3,2,3],[4,4,4]])
>> y = set(x)
TypeError: unhashable type: \'num
The above answers work if you want to create a set out of the elements contained in an ndarray
, but if you want to create a set of ndarray
objects – or use ndarray
objects as keys in a dictionary – then you'll have to provide a hashable wrapper for them. See the code below for a simple example:
from hashlib import sha1
from numpy import all, array, uint8
class hashable(object):
r'''Hashable wrapper for ndarray objects.
Instances of ndarray are not hashable, meaning they cannot be added to
sets, nor used as keys in dictionaries. This is by design - ndarray
objects are mutable, and therefore cannot reliably implement the
__hash__() method.
The hashable class allows a way around this limitation. It implements
the required methods for hashable objects in terms of an encapsulated
ndarray object. This can be either a copied instance (which is safer)
or the original object (which requires the user to be careful enough
not to modify it).
'''
def __init__(self, wrapped, tight=False):
r'''Creates a new hashable object encapsulating an ndarray.
wrapped
The wrapped ndarray.
tight
Optional. If True, a copy of the input ndaray is created.
Defaults to False.
'''
self.__tight = tight
self.__wrapped = array(wrapped) if tight else wrapped
self.__hash = int(sha1(wrapped.view(uint8)).hexdigest(), 16)
def __eq__(self, other):
return all(self.__wrapped == other.__wrapped)
def __hash__(self):
return self.__hash
def unwrap(self):
r'''Returns the encapsulated ndarray.
If the wrapper is "tight", a copy of the encapsulated ndarray is
returned. Otherwise, the encapsulated ndarray itself is returned.
'''
if self.__tight:
return array(self.__wrapped)
return self.__wrapped
Using the wrapper class is simple enough:
>>> from numpy import arange
>>> a = arange(0, 1024)
>>> d = {}
>>> d[a] = 'foo'
Traceback (most recent call last):
File "", line 1, in
TypeError: unhashable type: 'numpy.ndarray'
>>> b = hashable(a)
>>> d[b] = 'bar'
>>> d[b]
'bar'