Callback to .delay()

Question

I have an $image that I .fadeIn and .fadeOut, and then .remove after .fadeOut completes. This is my code:

Answer 1

You can use the queue() method to schedule your own function to run after delay() completes:

$image.fadeIn()
      .fadeOut()
      .delay(1000)
      .queue(function(next) {
          $(this).remove();
          next();
      });