Divide two variables in bash

Question

I am trying to divide two var in bash, this is what I\'ve got:

var1=3;
var2=4;

echo ($var1/$var2)

I always get a syntax error. Does anyone

Answer 1

If you want to do it without bc, you could use awk:

$ awk -v var1=3 -v var2=4 'BEGIN { print  ( var1 / var2 ) }'
0.75