Maybe this is a silly question, but I cannot seem to find an obvious answer.
I need a concurrent FIFO queue that contains only unique values. Attempting to add a val
A simple answer for a queue of unique objects can be as follow:
import java.util.concurrent.ConcurrentLinkedQueue;
public class FinalQueue {
class Bin {
private int a;
private int b;
public Bin(int a, int b) {
this.a = a;
this.b = b;
}
@Override
public int hashCode() {
return a * b;
}
public String toString() {
return a + ":" + b;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Bin other = (Bin) obj;
if ((a != other.a) || (b != other.b))
return false;
return true;
}
}
private ConcurrentLinkedQueue queue;
public FinalQueue() {
queue = new ConcurrentLinkedQueue();
}
public synchronized void enqueue(Bin ipAddress) {
if (!queue.contains(ipAddress))
queue.add(ipAddress);
}
public Bin dequeue() {
return queue.poll();
}
public String toString() {
return "" + queue;
}
/**
* @param args
*/
public static void main(String[] args) {
FinalQueue queue = new FinalQueue();
Bin a = queue.new Bin(2,6);
queue.enqueue(a);
queue.enqueue(queue.new Bin(13, 3));
queue.enqueue(queue.new Bin(13, 3));
queue.enqueue(queue.new Bin(14, 3));
queue.enqueue(queue.new Bin(13, 9));
queue.enqueue(queue.new Bin(18, 3));
queue.enqueue(queue.new Bin(14, 7));
Bin x= queue.dequeue();
System.out.println(x.a);
System.out.println(queue.toString());
System.out.println("Dequeue..." + queue.dequeue());
System.out.println("Dequeue..." + queue.dequeue());
System.out.println(queue.toString());
}
}