Sum of the digits of the number 2^1000 [closed]

Answer 1

Here is my code... Please provide the necessary arguments to run this code.

import java.math.BigInteger;

public class Question1 {
    private static int SumOfDigits(BigInteger inputDigit) {
        int sum = 0;
        while(inputDigit.bitLength() > 0) {
            sum += inputDigit.remainder(new BigInteger("10")).intValue();
            inputDigit = inputDigit.divide(new BigInteger("10"));       
        }                       
        return sum;
    }

    public static void main(String[] args) {
        BigInteger baseNumber = new BigInteger(args[0]);
        int powerNumber = Integer.parseInt(args[1]);
        BigInteger powerResult = baseNumber.pow(powerNumber);
        System.out.println(baseNumber + "^" + powerNumber + " = " + powerResult);
        System.out.println("Sum of Digits = " + Question1.SumOfDigits(powerResult));
    }

}