what is difference between integer a = 5 and new Integer(5)?

Question

if i write below code(in java):

Integer a =new Integer(5);
Integer b=new Integer(5);
if(a==b){
  System.out.println(\"In ==\");
}
if(a.equals(b)){
 System.o         


        

Answer 1

Integer a = 5; is called autoboxing, compiler converts this expression into actual

Integer a = Integer.valueOf(5);

For small numbers, by default -128 to 127, Integer.valueOf(int) does not create a new instance of Integer but returns a value from its cache. So here

Integer a = 5;
Integer b= 5;

a and b point to the same Object and a == b is true.