Why is address of char data not displayed?

Question

class Address {
      int i ;
      char b;
      string c;
      public:
           void showMap ( void ) ;
};

void Address :: showMap ( void ) {
            cout          


        

Answer 1

The address of char is being treated as a nul-terminated string and is displaying the contents of that address, which is probably undefined, but in this case an empty string. If you cast the pointers to void *, you will get the results you desire.

The difference between something2 and something being 8 is due to aligned and ability of the compiler to decide for itself where in the stack the variables are declared.