How to escape the % (percent) sign in C's printf?

Question

How do you escape the % sign when using printf in C?

printf(\"hello\\%\"); /* not like this */

Answer 1

As others have said, %% will escape the %.

Note, however, that you should never do this:

char c[100];
char *c2;
...
printf(c); /* OR */
printf(c2);

Whenever you have to print a string, always, always, always print it using

printf("%s", c)

to prevent an embedded % from causing problems [memory violations, segfault, etc]