How do you escape the % sign when using printf in C?
printf
printf(\"hello\\%\"); /* not like this */
You can escape it by posting a double '%' like this: %%
%%
Using your example:
printf("hello%%");
Escaping '%' sign is only for printf. If you do:
char a[5]; strcpy(a, "%%"); printf("This is a's value: %s\n", a);
It will print: This is a's value: %%
This is a's value: %%