Select along one of n dimensions in array

后端 未结 4 1322
青春惊慌失措
青春惊慌失措 2020-12-05 19:53

I have an array in R, created by a function like this:

A <- array(data=NA, dim=c(2,4,4), dimnames=list(c(\"x\",\"y\"),NULL,NULL))

And I

4条回答
  •  一向
    一向 (楼主)
    2020-12-05 20:18

    I spent quite a lot of time figuring out the fastest way to do this for plyr, and the best I could come up with was manually constructing the call to [:

    index_array <- function(x, dim, value, drop = FALSE) { 
      # Create list representing arguments supplied to [
      # bquote() creates an object corresponding to a missing argument
      indices <- rep(list(bquote()), length(dim(x)))
      indices[[dim]] <- value
    
      # Generate the call to [
      call <- as.call(c(
        list(as.name("["), quote(x)),
        indices,
        list(drop = drop)))
      # Print it, just to make it easier to see what's going on
      print(call)
    
      # Finally, evaluate it
      eval(call)
    }
    

    (You can find more information about this technique at https://github.com/hadley/devtools/wiki/Computing-on-the-language)

    You can then use it as follows:

    A <- array(data=NA, dim=c(2,4,4), dimnames=list(c("x","y"),NULL,NULL))
    index_array(A, 2, 2)
    index_array(A, 2, 2, drop = TRUE)
    index_array(A, 3, 2, drop = TRUE)
    

    It would also generalise in a straightforward way if you want to extract based on more than one dimension, but you'd need to rethink the arguments to the function.

提交回复
热议问题