“Address of” (&) an array / address of being ignored be gcc?

Question

I am a teaching assistant of a introductory programming course, and some students made this type of error:

char name[20];
scanf(\"%s\",&name);
         


        

Answer 1

If You define an array like

char name[20];

name is implicitly convertible to char*, but &name is of the type char (*)[20] (a pointer to an array of 20 characters). The addresses are the same.

Check the address of (&name + 1). It differs form &name by the sizeof(char [20]).