Regular Expression to get a string between parentheses in Javascript

Question

I am trying to write a regular expression which returns a string which is between parentheses. For example: I want to get the string which resides between the strings \"(\"

Answer 1

To match a substring inside parentheses excluding any inner parentheses you may use

\(([^()]*)\)

pattern. See the regex demo.

In JavaScript, use it like

var rx = /\(([^()]*)\)/g;

Pattern details

• \( - a ( char
• ([^()]*) - Capturing group 1: a negated character class matching any 0 or more chars other than ( and )
• \) - a ) char.

To get the whole match, grab Group 0 value, if you need the text inside parentheses, grab Group 1 value.

Most up-to-date JavaScript code demo (using matchAll):

const strs = ["I expect five hundred dollars ($500).", "I expect.. :( five hundred dollars ($500)."];
const rx = /\(([^()]*)\)/g;
strs.forEach(x => {
  const matches = [...x.matchAll(rx)];
  console.log( Array.from(matches, m => m[0]) ); // All full match values
  console.log( Array.from(matches, m => m[1]) ); // All Group 1 values
});

Legacy JavaScript code demo (ES5 compliant):

var strs = ["I expect five hundred dollars ($500).", "I expect.. :( five hundred dollars ($500)."];
var rx = /\(([^()]*)\)/g;


for (var i=0;i