Why won't passing `''.trim()` straight to `[].map()`'s callback work?

Question

I have an array of strings. I want to trim each string in the array.

I thought using [].map() with \'\'.trim() would work...

[\' a\', \' b   \', \'c         


        

Answer 1

With ES6 syntax it can be as easy as this:

[' hello  ', '  world'].map(str => str.trim());