Conversion from 'myItem*' to non-scalar type 'myItem' requested

Question

I have this C++ code:

#include 
using namespace std;
struct MyItem
{
  int value;
  MyItem* nextItem;
};

int main() {
    MyItem item = new          


        

Answer 1

You've mixed

MyItem item;

which allocates an instance of MyItem on the stack. The memory for the instance is automatically freed at the end of the enclosing scope

and

MyItem * item = new MyItem;

which allocates an instance of MyItem on the heap. You would refer to this instance using a pointer and would be required to explicitly free the memory when finished using delete item.