Find last match with python regular expression

Question

I want to match the last occurrence of a simple pattern in a string, e.g.

list = re.findall(r\"\\w+ AAAA \\w+\", \"foo bar AAAA foo2 AAAA bar2\")
print \"las         


        

Answer 1

you could use $ that denotes end of the line character:

>>> s = """foo bar AAAA
foo2 AAAA bar2"""
>>> re.findall(r"\w+ AAAA \w+$", s)
['foo2 AAAA bar2']

Also, note that list is a bad name for your variable, as it shadows built-in type. To access the last element of a list you could just use [-1] index:

>>> lst = [2, 3, 4]
>>> lst[-1]
4