Comparing two integers without any comparison

Question

Is it possible to find the greatest of two integers without any comparison? I found some solutions:

if(!(a/b)) // if a is less than b then division result          


        

Answer 1

Not one of the samples presented in the question or any of the answers thus far protects from division by zero. Why on earth are you trying to avoid an 'if' statement? I suspect homework question about ?: operators.

cout << "Maximum is: " << ((a>b)?a:b)

There we go.

It's not possible to compare two numbers without a comparison. You can fudge it and do an indirect operation, but at the end of the day you're comparing something. Trust the compiler to optimize the code and select the best operations.