Numpy `logical_or` for more than two arguments

Question

Numpy\'s logical_or function takes no more than two arrays to compare. How can I find the union of more than two arrays? (The same question could be asked wit

Answer 1

I use this workaround which can be extended to n arrays:

>>> a = np.array([False, True, False, False])
>>> b = np.array([True, False, False, False])
>>> c = np.array([False, False, False, True])
>>> d = (a + b + c > 0) # That's an "or" between multiple arrays
>>> d
array([ True,  True, False,  True], dtype=bool)