Numpy `logical_or` for more than two arguments

Question

Numpy\'s logical_or function takes no more than two arrays to compare. How can I find the union of more than two arrays? (The same question could be asked wit

Answer 1

In case someone still need this - Say you have three Boolean arrays a, b, c with the same shape, this gives and element-wise:

a * b * c

this gives or:

a + b + c

Is this what you want? Stacking a lot of logical_and or logical_or is not practical.