Difference between pointer to pointer and pointer to array?

Question

Given that the name of an array is actually a pointer to the first element of an array, the following code:

#include 

int main(void)
{
    in         


        

Answer 1

Line 11 is

        p1 = &a;

where p1 has type int ** and a has type int[3], right?

Well; &a has type int(*)[3] and that type is not compatible with int** as the compiler told you

You may want to try

        p1 = &p0;

And read the c-faq, particularly section 6.

In short: arrays are not pointers, and pointers are not arrays.