.is(“:hover”) is broken as of jQuery 1.9 How to fix

Question

When doing $(...your selector here...).is(\":hover\"), jQuery prior to 1.9.1 gave correct answer, while jQuery 1.9.1 tells you this:

Erro

Answer 1

However the workaround above is unsuitable when you are comparing elements using jQuery.fn.is() with a composed selector which is not known beforehand, and that could match several elements in the parent container.

eg, the same exception is thrown when selectorText in style_get() below is equal to: ".mCSB_scrollTools_vertical.mCSB_scrollTools_onDrag_expand .mCSB_dragger.mCSB_dragger_onDrag_expanded .mCSB_dragger_bar, .mCSB_scrollTools_vertical.mCSB_scrollTools_onDrag_expand .mCSB_draggerContainer:hover .mCSB_dragger .mCSB_dragger_bar"

..because hover is not defined in Sizzle.selectors.pseudos or Sizzle.selectors.setFilters (jquery-2.1.4, line 1764)..

function style_get(elem) {

  var sheets=document.styleSheets;
  var css_properties={};
  elem=$(elem);

  for (var s in sheets) {
    var rules=sheets[s].rules || sheets[s].cssRules;

    for (var r in rules) {
      if (elem.is(rules[r].selectorText)) {

        css_properties=$.extend(
          css_properties,
          css.parse(rules[r].style),
          css.parse(elem.attr('style'))
        );

      }
    }

  }

  return css_properties;

}