“new BigDecimal(13.3D)” results in imprecise “13.3000000000000007105..”?

Question

How is it that Java\'s BigDecimal can be this painful?

Double d = 13.3D;

BigDecimal bd1 = new BigDecimal(d);
BigDecimal bd2 = new BigDecimal(St         


        

Answer 1

This isn't the fault of BigDecimal - it's the fault of double. BigDecimal is accurately representing the exact value of d. String.valueOf is only showing the result to a few decimal places.