Sort version-dotted number strings in Javascript?

Question

I have an array of following strings:

[\'5.5.1\', \'4.21.0\', \'4.22.0\', \'6.1.0\', \'5.1.0\', \'4.5.0\'] 

...etc.

I need a soluti

Answer 1

This can be in an easier way using the sort method without hardcoding any numbers and in a more generic way.

enter code here

var arr = ['5.1.2', '5.1.1', '5.1.1', '5.1.0', '5.7.2.2'];

splitArray = arr.map(elements => elements.split('.'))

//now lets sort based on the elements on the corresponding index of each array

//mapped.sort(function(a, b) {
//  if (a.value > b.value) {
//    return 1;
//  }
//  if (a.value < b.value) {
//    return -1;
//  }
//  return 0;
//});

//here we compare the first element with the first element of the next version number and that is [5.1.2,5.7.2] 5,5 and 1,7 and 2,2 are compared to identify the smaller version...In the end use the join() to get back the version numbers in the proper format.

sortedArray = splitArray.sort((a, b) => {
  for (i in a) {
    if (parseInt(a[i]) < parseInt(b[i])) {
      return -1;
      break
    }
    if (parseInt(a[i]) > parseInt(b[i])) {
      return +1;
      break
    } else {
      continue
    }
  }
}).map(p => p.join('.'))

sortedArray = ["5.1.0", "5.1.1", "5.1.1", "5.1.2", "5.7.2.2"]