how to get the caller's filename, method name in python

Question

for example, a.boo method calls b.foo method. In b.foo method, how can I get a\'s file name (I don\'t want to pass __file__

Answer 1

you can use the traceback module:

import traceback

and you can print the back trace like this:

print traceback.format_stack()

I haven't used this in years, but this should be enough to get you started.