Any way faster than pow() to compute an integer power of 10 in C++?

Question

I know power of 2 can be implemented using << operator. What about power of 10? Like 10^5? Is there any way faster than pow(10,5) in C++? It is a pretty straight-forw

Answer 1

result *= 10 can also be written as result = (result << 3) + (result << 1)

constexpr int pow10(int n) {
  int result = 1;
  for (int i = 0; i < n; i++) {
    result = (result << 3) + (result << 1);
  }
  return result;
}