Any way faster than pow() to compute an integer power of 10 in C++?

Question

I know power of 2 can be implemented using << operator. What about power of 10? Like 10^5? Is there any way faster than pow(10,5) in C++? It is a pretty straight-forw

Answer 1

if you want to calculate, e.g.,10^5, then you can:

int main() {
   cout << (int)1e5 << endl; // will print 100000
   cout << (int)1e3 << endl; // will print 1000
   return 0;
}