Meaning of default initialization changed in C++11?

Question

C++2003 8.5/5 says:

To default-initialize an object of type T means:

— if T is a non-POD class type (clause 9), the default const

Answer 1

According to cppreference.com (because it uses friendlier language than the standard):

Default initialization is performed in three situations:

3) when a base class or a non-static data member is not mentioned in a constructor initializer list and that constructor is called.

Value initialization is performed in three situations:

3,7) when a non-static data member or a base class is initialized using a member initializer with an empty pair of parentheses or braces (since C++11)

Note that the C++11 part belongs with the or braces, not with the entire paragraph.

And:

To value-initialize an object of type T means:
— if T is an array type, then each element is value-initialized;
— otherwise, the object is zero-initialized

So in C++11 default-initialization does not zero-initialize members but value-initialization does.