How to call an explicitly implemented interface-method on the base class

Question

I have a situation, where two classes (one deriving from the other) both implement the same interface explicitly:

interface I
{
  int M();
}

class A : I
{
          


        

Answer 1

Here is my version of Roland Pihlakas's nice solution. This version supports the entire inheritance chain instead of immediate base class. The Invoke method includes additional parameters and there is a void type Invoke for non-function methods.

public class BaseClassExplicitInterfaceInvoker
{
    readonly Dictionary Cache = new Dictionary();

    MethodInfo FindMethod(string MethodName)
    {
        if (Cache.TryGetValue(MethodName, out var Result)) return Result;

        var BaseType = typeof(T);
        while (Result == null)
        {
            if ((BaseType = BaseType.BaseType) == typeof(object)) break;

            var Methods = BaseType.GetMethods(BindingFlags.NonPublic | BindingFlags.Instance | BindingFlags.DeclaredOnly);
            Result = Methods.FirstOrDefault(X => X.IsFinal && X.IsPrivate && (X.Name == MethodName || X.Name.EndsWith("." + MethodName)));
        }

        if (Result != null) Cache.Add(MethodName, Result);

        return Result;
    }

    public void Invoke(T Object, string MethodName, params object[] Parameters) => FindMethod(MethodName).Invoke(Object, Parameters);
    public ReturnType Invoke(T Object, string MethodName, params object[] Parameters) => (ReturnType)FindMethod(MethodName).Invoke(Object, Parameters);
}