How do you store a list of directories into an array in Bash (and then print them out)?

Question

I want to write a shell script to show a list of directories entered by a user and then for a user to select one of the directories with an index number based on how many di

Answer 1

Update: my answer is wrong

Leaving it here to address a common misunderstanding, below the line is erroneous.

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To put the directories in an array you can do...

array=( $( ls -1p | grep / | sed 's/^\(.*\)/"\1"/') )

This will capture the dir names, including those with spaces.

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Extracting from comments:

literal quotes don't have any effect on string-splitting, so array=( echo '"hello world" "goodbye world"' ) is an array with four elements, not two

@Charles Duffy

Charles also supplied the following link Bash FAQ #50 which is an extended discussion on this issue.

I should also draw attention to the link posted by @Dennis Williamson - why I shouldn't have used ls