Passing a property as an 'out' parameter in C#

Question

Suppose I have:

public class Bob
{
    public int Value { get; set; }
}

I want to pass the Value member as an out parameter like

Answer 1

You can achieve that, but not with a property.

public class Bob {
    public int Value { get; set; } // This is a property

    public int AnotherValue; // This is a field
}

You cannot use out on Value, but you can on AnotherValue.

This will work

Int32.TryParse("123", out bob.AnotherValue);

But, common guidelines tells you not to make a class field public. So you should use the temporary variable approach.