Why pow(10,5) = 9,999 in C++

Question

Recently i write a block of code:

const int sections = 10;

for(int t= 0; t < 5; t++){
   int i = pow(sections, 5- t -1);  
   cout << i << en         


        

Answer 1

There must be some broken pow function in the global namespace. Then std::pow is "automatically" used instead in your second example because of ADL.

Either that or t is actually a floating-point quantity in your first example, and you're running into rounding errors.