c code:
// program break mechanism
// TLPI exercise 7-1
#include
#include
void program_break_test() {
printf(\"%10p\\n
If you use malloc in your code, it will call brk() at the beginning, allocated 0x21000 bytes from the heap, that's the address you printed, so the Question 1: the following mallocs requirements can be meet from the pre-allocated space, so these mallocs actually did't call brk, it is a optimization in malloc. If next time you want to malloc size beyond that boundary, a new brk will be called (if not large than the mmap threshold).