zipWith (mapping over multiple Seq) in Scala

Question

Suppose I have

val foo : Seq[Double] = ...
val bar : Seq[Double] = ...

and I wish to produce a seq where the baz(i) = foo(i) + bar(i). One

Answer 1

Well, that, the lack of zip, is a deficiency in Scala's 2.7 Seq. Scala 2.8 has a well-thought collection design, to replace the ad-hoc way the collections present in 2.7 came to be (note that they weren't all created at once, with an unified design).

Now, when you want to avoid creating temporary collection, you should use "projection" on Scala 2.7, or "view" on Scala 2.8. This will give you a collection type for which certain instructions, particularly map, flatMap and filter, are non-strict. On Scala 2.7, the projection of a List is a Stream. On Scala 2.8, there is a SequenceView of a Sequence, but there is a zipWith right there in the Sequence, you wouldn't even need it.

Having said that, as mentioned, JVM is optimized to handle temporary object allocations, and, when running in server mode, the run-time optimization can do wonders. So, do not optimize prematurely. Test the code in the conditions it will be run -- and if you haven't planned to run it in server mode, then rethink that if the code is expected to be long-running, and optmize when/where/if necessary.

EDIT

What is actually going to be available on Scala 2.8 is this:

(foo,bar).zipped.map(_+_)