Type condition in template

Question

Is it possible to build only some part of the code given the type of the template in C++ ? It would be something lake that :

#include 

using         


        

Answer 1

You use template specification to specify versions of your function to work differently based on its type. For example, you can make a generic version of a function that would work with most types, and make a specific version for e.g. int that will be faster. You'd do it this way:

template 
void printType(T param)
{
    cout<<"Generic version"<
void printType(int param)
{
    cout<<"Int version"<
void printType(char param)
{
    cout<<"Char version"<