Valid Java code that is NOT valid Groovy code?

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忘了有多久
忘了有多久 2020-12-05 04:50

Most Java code is also syntactically valid Groovy code. However, there are a few exceptions which leads me to my question:

Which constructs/features in Java are syn

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  •  感动是毒
    2020-12-05 05:27

    Here is a list of items that are valid Java 6, but not valid Groovy 1.6. This isn't a complete list, but I think it covers most of the cases. Some of these are permitted by later Groovy versions as noted below.

    (By the way, I think you should note that non-static initialization blocks DO work in Groovy.)

    Any inner class declaration in Groovy 1.6 (1.7 added inner classes):

    including static,

    public class Outer{
      static class Inner{}
    }
    

    non-static,

    public class Outer{
      class Inner{}
    }
    

    local classes,

    public class Outer{
      public static void main(String[] args) {
        class Local{}  
      }
    }
    

    and anonymous classes

    java.util.EventListener listener=new java.util.EventListener(){};
    

    Using Groovy keywords as variables won't work in any Groovy version:

    int def;
    int in;
    int threadsafe;
    int as;
    

    Java array initialization

    String[] stuff=new String[]{"string"};
    int[] array={1,2,3};
    

    Use the Groovy array-literal format by changing {...} to [...].

    Using dollar signs in strings where what follows isn't a valid expression

    String s="$$";
    String s="$def";
    String s="$enum";
    String s="$;";
    String s="$\\";
    //etc.
    

    More than one initializer in a for loop

    for (int i=0, j=0; i < 5; i++) {}
    

    More than one increment in a for loop

    int j=0;
    for (int i=0; i < 5; i++,j++) {}
    

    Breaking up some expressions using newlines

    int a= 2 
    / 2 
    ;
    

    Hint: use a backslash line-continuation in Groovy

    int a= 2 \
    / 2 \
    ;
    

    Ending switch with a case that has no body

    switch(a){
      case 1:
    }
    

    Having a default in a switch with no body

    Applies in both cases where default is at the end

    int a=0;
    switch(a){
        default:
    }
    

    or somewhere in the middle

    switch(a){
        default:
        case 1:
            break;
    }
    

    Annotations with lists

    @SuppressWarnings({"boxing","cast"})
    

    Hint: use Groovy list-literal syntax instead:

    @SuppressWarnings(["boxing","cast"])
    

    Native method declaration

    public native int nativeMethod();
    

    **Class per enum in 1.6 (valid in later Groovy versions) **

    public enum JavaEnum{
      ADD{
        public String getSymbol(){ return "+"; }
      };
      abstract String getSymbol();
    }
    

    Do loop

    do{
      System.out.println("stuff");
    }while(true);
    

    Equality

    While technically == is valid Groovy and Java, it's semantically different. It's one of the reasons you can't rely on just compiling Java as Groovy without changes. Worse, it might seem to work sometimes due to Java string interning.

    The example was too long to add to an existing answer, but the point is that Java code that's syntatically valid as Groovy might behave differently at runtime.

    To get the same result as Java's x == y for two not-null objects you need x.is(y) in Groovy. x == y is valid Groovy, it just does something different.

    The Groovy documentation has a more detailed and broader list of differences.

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