Preserving quotes in bash function parameters

Question

What I\'d like to do is take, as an input to a function, a line that may include quotes (single or double) and echo that line exactly as it was provided to the function. For

Answer 1

doit echo "'single quote $VAR'"
doit echo '"double quote $VAR"'

Both will work.

bash will only strip the outside set of quotes when entering the function.