How to “perfectly” override a dict?

Question

How can I make as \"perfect\" a subclass of dict as possible? The end goal is to have a simple dict in which the keys are lowercase.

It would seem

Answer 1

All you will have to do is

class BatchCollection(dict):
    def __init__(self, *args, **kwargs):
        dict.__init__(*args, **kwargs)

OR

class BatchCollection(dict):
    def __init__(self, inpt={}):
        super(BatchCollection, self).__init__(inpt)

A sample usage for my personal use

### EXAMPLE
class BatchCollection(dict):
    def __init__(self, inpt={}):
        dict.__init__(*args, **kwargs)

    def __setitem__(self, key, item):
        if (isinstance(key, tuple) and len(key) == 2
                and isinstance(item, collections.Iterable)):
            # self.__dict__[key] = item
            super(BatchCollection, self).__setitem__(key, item)
        else:
            raise Exception(
                "Valid key should be a tuple (database_name, table_name) "
                "and value should be iterable")

Note: tested only in python3