Python - Flask Default Route possible?

Question

In Cherrypy it\'s possible to do this:

@cherrypy.expose
def default(self, url, *suburl, **kwarg):
    pass

Is there a flask equivalent?

Answer 1

@app.errorhandler(404)
def handle_404(e):
    # handle all other routes here
    return 'Not Found, but we HANDLED IT