Are all temporaries rvalues in C++?

Question

I have been coding in C++ for past few years. But there is one question that I have not been able to figure out. I want to ask, are all temporaries in C++, rvalues?

Answer 1

If no, can anyone provide me an example where temporary produced in the code is an lvalue?

The following code binds a constant reference to a temporary object of type const float created by the compiler:

int i;
const float &cfr = i;

The behaviour is "as if":

int i;
const float __tmp_cfr = i; // introduced by the compiler
const float &cfr = __tmp_cfr;