Sorting on the last field of a line

Question

What is the simplest way to sort a list of lines, sorting on the last field of each line? Each line may have a variable number of fields.

Something like

Answer 1

| sed "s#(.*)/#\1"\\$'\x7F'\# \
| sort -t\\$'\x7F' -k2,2 \
| sed s\#\\$'\x7F'"#/#"

Still way worse than simple negative field indexes for sort(1) but using the DEL character as delimiter shouldn’t cause any problem in this case.

I also like how symmetrical it is.